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Arithmetic and geometric together

Solve the first problem 18 problems

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  1. Positive x in a sequence of squares ●○○○○ 10 ptsThe numbers 121^2, x2x^2, 323^2 are consecutive terms of an arithmetic sequence. Find the positive value of xx. Round to two decimal places.
  2. Middle term of an arithmetic sequence ●○○○○ 10 ptsIn the arithmetic sequence 32,x,343^2, x, 3^4, find the value of xx.
  3. Harmonic numbers ●○○○○ 10 ptsCall three numbers a,b,ca, b, c harmonic when their reciprocals form an arithmetic sequence, that is, 1a−1b=1b−1c\frac{1}{a}-\frac{1}{b}=\frac{1}{b}-\frac{1}{c}. For example, 15,12,1015, 12, 10 are harmonic because 112−115=110−112\frac{1}{12}-\frac{1}{15}=\frac{1}{10}-\frac{1}{12}. Given that xx, 55, 33 are harmonic numbers in this order with x>5x>5, find xx.
  4. Least difference between geometric and arithmetic terms ●●○○○ 20 ptsSequence AA is a geometric sequence and sequence BB is an arithmetic sequence. Each sequence stops as soon as one of its terms is greater than 300300. Sequence AA: 2,4,8,16,32,…2, 4, 8, 16, 32, \ldots. Sequence BB: 20,40,60,80,100,…20, 40, 60, 80, 100, \ldots. Find the least positive difference between a number selected from sequence AA and a number selected from sequence BB.
  5. Greatest third term of an arithmetic sequence ●●○○○ 20 ptsThe sum of four positive integers that form an arithmetic sequence is 46. Of all such possible sequences, what is the greatest possible third term?
  6. Greatest number from two sequences ●●○○○ 20 ptsWhat is the greatest three-digit number abc‾\overline{abc} such that 4,a,b4, a, b form a geometric sequence and b,c,5b, c, 5 form an arithmetic sequence? Here aa, bb, cc are digits.
  7. Arithmetic then geometric progression integers ●●●○○ 50 ptsThree distinct integers aa, bb, cc satisfy the following conditions: - abc=17955abc = 17955; - aa, bb, cc are three consecutive terms of an arithmetic sequence, in that order; - 3a+b3a+b, 3b+c3b+c, 3c+a3c+a are three consecutive terms of a geometric sequence, in that order. Find a+b+ca+b+c.
  8. Integer trapped between two sequences ●●●○○ 50 ptsLet {an}\{a_n\} and {bn}\{b_n\} be sequences with a1=0a_1=0 and b1=2013b_1=2013, such that for every positive integer nn the triples (an,an+1,bn)(a_n, a_{n+1}, b_n) and (an+1,bn+1,bn)(a_{n+1}, b_{n+1}, b_n) are arithmetic sequences. Find the unique positive integer cc such that an<c<bna_n < c < b_n for all positive integers nn.
  9. Sum of four progression terms ●●●○○ 50 ptsIn an increasing sequence of four positive integers, the first three terms form an arithmetic progression, the last three terms form a geometric progression, and the first and fourth terms differ by 3030. Find the sum of the four terms.

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