Mathegoras

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Angle CBD in a tetrahedron

High school · ●●○○○ 20 pts

In tetrahedron ABCDABCD, BC=1BC=1, BD=2BD=2, ∠ABC=90∘\angle ABC=90^{\circ}, and BC→⋅DA→=−3\overrightarrow{BC}\cdot\overrightarrow{DA}=-\sqrt{3}. Find ∠CBD\angle CBD in degrees.

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dot productangle between vectorslaw of cosinesregular tetrahedron